Dc to Ac Simulation Result 2

Dc to Ac Simulation Result 1

Dc to Ac Schematic 2

Dc to Ac Schematic 1

DC-to-DC: Analysis of Circuit Simulation

Above schematic is created from OrCAD PSpice. The components used in this circuit are MC34063 (as the main component), resistors (4), electrolytic capacitor (3), inductor (2), capacitor (1) and Schottky diode (1).

Project Planner Trimester 3

WEEK	DATE	PROGRESS
1, 2, 3, 4 & 5	2 Feb – 8 Mac 2008	Continue from FYP part 1, Enhancement, Construct Final Circuit, Troubleshooting & Enhancement.
6 & 7	9 Mac – 22 Mac 2008	Documentation
	23 Mac – 29 Mac 2008	MIDTERM BREAK
8, 9, 10 & 11	30 Mac – 26 April 2008	Final Report writing & submitting
12 & 13	27 April – 3 May 2008	Presentation FYP

DC-to-DC: Circuit Explanation - Buck Converter

The circuit on the left is the basic circuit of the step down converter. The input electric power is sent to the output circuit by the switching operation of the regulator. The coil of the output circuit stores up the input electric power when TR is ON. Then, it slips the electrical energy which was stored up when TR was OFF to the output and it supplies the load with the electric power. The capacitor of the output circuit does the supply of electric power to the load in the leveling like the coil.

When TR is ON, the input electric power is supplied to the capacitor (C2) and the load through the coil (L1). At this time, the electrical energy is stored up at the coil (L1) and the capacitor (C2). At this time, the side of the input of the coil becomes positive and the side of the output becomes the negative potential.
When TR becomes OFF, the coil slips the electrical energy which was stored up by trying to continue to pass the electric current.(Lenz's law) At this time, the side of the input of the coil becomes negative and the side of the output becomes the positive potential. It becomes such potential because it tries to continue to pass the electric current. The electrical energy which was stored up at the coil is supplied through the load and the diode. When there is not a diode, the electrical energy which was stored up at the coil can not be supplied. At this time, the electrical energy which was stored up at the capacitor is supplied to the load too.


The input electric power is again applied through TR when TR becomes ON. This electric power is supplied to the load but the part is stored up at the coil and the capacitor. When the countercurrent isn't prevented with the diode when TR becomes ON, the input electric power flows to the ground through the diode and isn't supplied to the load. Because it is, the diode must be used the the shottky barrier diode or the first recovery diode.

This is how buck converter should work. On theory, 12VDC would be reduce to 5VDC (project's desired voltage) without problem. Now, it comes to some analysis before going to circuit test.
Bring it on!!! :wink: